Question

One of the largest rectangular omelets ever cooked had a perimeter of 80 feet. The length was 10 feet more than twice its width. How many feet wide was the omelet?

Answer 1

l= w + 10
l = w = 80

Answer 2

l + w= 80*

Answer 3

i guess it might be a rectangle
hence as said let width be; x, hence length will be ; 2x + 10
perimeter is 2l + 2w
hence add substituting the values
2(x + 2x +10) = 80
divide by 2
3x + 10 = 40
subtract be 10
3x = 30
x = 10
hence
width and length are
30 and 70

Answer 4

But that together is already more thatn 80...

Answer 5

trueeee^^^

Answer 6

oops i wrote x = 10
m such a dumb;
length = 10 and width equals 30

Answer 7

i guess it might be a rectangle hence as said let width be; x, hence length will be ; 2x + 10 perimeter is 2l + 2w hence add substituting the values 2(x + 2x +10) = 80 divide by 2 3x + 10 = 40 subtract be 10 3x = 30 x = 10 hence width and length are 10 and 30 respectively,
heres whole solution ;)