Question

rationalize denominator of 3/2+ the square root of 3

Answer 1

if this is the question you will need to multiply by 1

\[\frac{3}{2+\sqrt{3}}\]

by 1 is written as

\[\frac{2 - \sqrt{3}}{2 - \sqrt{3}}\]

so you will get a rational number in the denominator

\[\frac{3}{2 + \sqrt{3}} \times \frac{ 2 - \sqrt{3}}{2 - \sqrt{3}}\]

Answer 2

thats why i got to when i did the problem then i could not figure out the solution. do u know how

Answer 3

what*

Answer 4

@lexigolds

Calculate the product of the numerators and the product of the denominators as @campbell_st has indicated.

To help you get started, the product of the numerators would be 3( 2 - sqrt(3) ) =
6 - 3*sqrt(3) (Use the Distributive Property).

Use multiplication of binomials technique with the denominators.