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derivative of radical x
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\[\sqrt x=x^{1/2}\] Apply the power rule from here :D
whats the power rule 1/2x^-.5 ?
yes
it said its wrong
its 1/4
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x=4?
\[\frac{ 1 }{ 2 }x^{-\frac{ 1 }{ 2 }}=\frac{ 1 }{ 2 }\frac{ 1 }{ \sqrt x }\]
yea
i guess ahah i didnt know that it mattered
yea once you find the derivative, you just plug in for x
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can you tell me this other one???
\[p(\Theta)=\sqrt{5\Theta} ;pprime(1)\]
\[p(\theta)=\sqrt{5\theta}=\sqrt{5}\theta^{1/2}\] \[p'(\theta)=\sqrt5 *(1/2)*\theta^{-1/2}=\frac{ \sqrt5 }{ 2\sqrt \theta }\] \[p'(1)=\frac{ \sqrt5 }{ 2\sqrt1 }=\frac{ \sqrt5 }{ 2 }\]
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