Question

find the derivative of the function.
g(t)=e (to the power of-3/t^2)

Answer 1

\[e^{\frac{-3}{t^2}}\]?

Answer 2

is it -3e to the power of t^2?

Answer 3

since the derivative of \(e^x\) is \(e^x\) your job is only to find the derivative of \(-\frac{3}{t^2}\) and multiply it by
\[e^{-\frac{3}{t^2}}\]

Answer 4

ok so i find what -3/t^2 is and then multiply it by e^x right?

Answer 5

no not by \(e^x\) but rather by \(e^{-\frac{3}{t^2}}\)

Answer 6

don't change the input for the "outside" function, leave it alone

Answer 7

o okay so it would be this -3/t^2 =====-3(t^-2) and then i could use the power rule right?

Answer 8

yes

Answer 9

kkkkkkkkk! so i would get 0 times t^-2 +-2t (0) right?

Answer 10

i mean -2t times -3

Answer 11

right?