Question

x²+x-2>0 factor

Answer 1

x²+x-2x-2 >0
x(x+1)-2(x+1) >0
(x-2)(x+1) >0

Answer 2

That is correct (:

Answer 3

what do i do from here on tho :S

Answer 4

Now all you do is set it up to x-2>0 and x+1>0 if I am not wrong so x>2 or x>-1.

Answer 5

yes but how do you come up with that ?

Answer 6

Hmm\[x^2+x-2>0 \rightarrow x^2+2x-x-2>0\]
I think the sign on your 2x is wrong maybe :O might wanna check that.

Answer 7

@zepdrix i think it's right both ways

Answer 8

\[x^2+x-2x-2 = x^2-x-2\]
which is not quite what you started with <:o

Answer 9

Hmm I've never had one of these o: