An object is dropped from ret from a height of 38.3m. What is its average acceleration (assumed to be constant) if it hits the ground with a speed of 1.75m/s?

Question

anonymous · Answer

vg^2=v0^2+2ah
you can use this

anonymous · Answer

but wouldnt the acceleration just be 9.8m/s^2?

anonymous · Answer

yes i tried that, and i got a value of 0.0399

anonymous · Answer

The acceleration could be 9.8, but it's not neccesarily true. The problem doesn't sepcify where experiment is being held. Maybe the moon? Or somewhere else in universe :)

anonymous · Answer

so the acceleration should be negative right?

anonymous · Answer

my calculation gives a positive value, but consider that it drops to the ground, should it be -ve

anonymous · Answer

Acceleration could be positive or negative, depend on your reference coordinate. If you take up as posiitve direction, than aceleration is negative. And yes, it's dropped with final velocity -ve

anonymous · Answer

but the initial velocity is 0m/s right

anonymous · Answer

correct, it said "dropped" not "thrown"

anonymous · Answer

ok thanks!

anonymous · Answer

I actually have one more question, plz take a look if u have time!

anonymous · Answer

NPP

anonymous · Answer

Just post it. Even if i can't another user will help you :)

anonymous · Answer

yep i did :)