How do i go about solving this question 10?
what is the derivative of f(x) = sin^2(x) ?
you should have a formula for that derivative somewhere :)
it is 2sinx cos x
I dont know where to go from that besides putting in the pi over 4 and using the unit circle points..
oh, well you're almost there... If you have that as the derivative... that expression is f'(x) f ' (x) = 2(sin (x) )(cos (x) ) and you need to evaluate at x = pi / 4
so f ' ( pi/4) = 2 sin (pi/4) cos (pi / 4)
2(root2/2)(root2/2)
then i dont understand what im supposed to do next
\[2\frac{ \sqrt{2} }{ 2 }\frac{ \sqrt{2} }{ 2 } = 2 \frac{ \sqrt{2}^{2} }{ 4 } = 2\frac{ (2) }{ 4 }\]
**mind blown*** why ? my teacher gave no examples like this btw. so im a noob
:) I love "mind status: blown" it's a sign of a curious (= healthy) person !! But no kidding... wish they'd teach you instead of leaving so much for you to discover on your own!!
oh wait i see it. i should get some sleep lol.
ahaha im silly i thought the = sign was a plus sign so i was like O.e sorcery! lol buuut i see it now. so it would just be 1
thanks so much!
yeah :) we both need some sleep :)
pretty sure that "sorcery" explains it all... :) that will laugh me off to sleep :)
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