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Mathematics 25 Online
OpenStudy (anonymous):

H E L P .. Me with this ONE 8] #Find p so that the curve f(x) = x 3 + 2 x 2 + p x + 3 has one horizontal tangent line only. # Find the value of x where this tangent line occurs. (\_/) (O_O) .(v v)

OpenStudy (anonymous):

And i wanna understand How u Did it =.=

OpenStudy (nubeer):

have u done derivatives?

OpenStudy (campbell_st):

ok... so you find the 1st derivative let it equal zero and then solve...

OpenStudy (anonymous):

O_O yeah .. but what is the point of doing the derivative

OpenStudy (anonymous):

=..= i feel so dump like never before :B

OpenStudy (campbell_st):

well the derivatives give the stationary points on a curve... or the equation of the gradient of the tangent....

OpenStudy (campbell_st):

but its an interesting question as the curve has only 1 max or min... or point where the gradient of the tangent = 0

OpenStudy (anonymous):

>_ > u know i should ask my teacher .. -_- it will be Better and easier :]

OpenStudy (nubeer):

take the first derivative and put equal to 0 , you will get an equation with "p" in it call this eq1.. then take the second derivative and put it equal to 0 , from here u will find the value of "x" susbstitute this value of x in eq1. you will get the value of p

OpenStudy (anonymous):

whats the P anyway o_o

OpenStudy (campbell_st):

its a coefficient of the term in x...

OpenStudy (anonymous):

ohh i see :l .. uhh calculus :B

OpenStudy (campbell_st):

yep.... all that rates of change stuff

OpenStudy (anonymous):

but i need to practice more . u kNoW <>_ <>

OpenStudy (anonymous):

Thanks anyway X3 .. thank you all guys <3 X]

OpenStudy (nubeer):

you're welcome

OpenStudy (anonymous):

XP

OpenStudy (anonymous):

I thought you were going to say something Mr. CamPbEll >_ >

OpenStudy (campbell_st):

the solution @nubeer gave works, you get a horizontal point of inflexion... as the only stationary point on the curve

OpenStudy (anonymous):

|dw:1348647900113:dw| ^_^ hehehe .. iim so dump to understand this .. just don't :P

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