H E L P .. Me with this ONE 8] #Find p so that the curve f(x) = x 3 + 2 x 2 + p x + 3 has one horizontal tangent line only. # Find the value of x where this tangent line occurs. (\_/) (O_O) .(v v)
And i wanna understand How u Did it =.=
have u done derivatives?
ok... so you find the 1st derivative let it equal zero and then solve...
O_O yeah .. but what is the point of doing the derivative
=..= i feel so dump like never before :B
well the derivatives give the stationary points on a curve... or the equation of the gradient of the tangent....
but its an interesting question as the curve has only 1 max or min... or point where the gradient of the tangent = 0
>_ > u know i should ask my teacher .. -_- it will be Better and easier :]
take the first derivative and put equal to 0 , you will get an equation with "p" in it call this eq1.. then take the second derivative and put it equal to 0 , from here u will find the value of "x" susbstitute this value of x in eq1. you will get the value of p
whats the P anyway o_o
its a coefficient of the term in x...
ohh i see :l .. uhh calculus :B
yep.... all that rates of change stuff
but i need to practice more . u kNoW <>_ <>
Thanks anyway X3 .. thank you all guys <3 X]
you're welcome
XP
I thought you were going to say something Mr. CamPbEll >_ >
the solution @nubeer gave works, you get a horizontal point of inflexion... as the only stationary point on the curve
|dw:1348647900113:dw| ^_^ hehehe .. iim so dump to understand this .. just don't :P
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