A starting lineup in basketball consists of two guards, two forwards, and a center. Now suppose the roster has 5 guards, 4 forwards, 3 centers, and 2 "swing players" (X and Y) who can play either guard or forward. If 5 of the 14 players are randomly selected, what is the probability that they constitute a legitimate starting lineup? (Round your answer to three decimal places.)

Question

A starting lineup in basketball consists of two guards, two forwards, and a center.   Now suppose the roster has 5 guards, 4 forwards, 3 centers, and 2 "swing players" (X and Y) who can play either guard or forward. If 5 of the 14 players are randomly selected, what is the probability that they constitute a legitimate starting lineup? (Round your answer to three decimal places.)

anonymous · Answer

I know how I'm supposed to solve this and I have solved it several times, my problem is that I'm supposed to put this answer on webassign and it's not accepting any of the solutions that I've posted.  I solve it as a combination/permutation problem and my final answer ends up being 

768/2002 which is 0.384 but webassign says no.  Could anyone offer any help maybe my professor is wrong and we aren't supposed to solve it this way?