Am I Correct? Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events. If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?
I got 64 as my answer
yep. it is ... area get's squared ... by the multiplication factor
ok so i am correct? just making sure.
if you want ... you can check. the area of pentagon is |dw:1348690593852:dw|
|dw:1348690780939:dw| you can use Sine law to find out other sides \[ {\sin A \over a} = {\sin B \over b} ={\sin C \over c}\] and total area = \( 5 \times {1 \over 2} \sin A \; b \times c\)
the initial side length wasn't really needed actually...
|dw:1348690909435:dw|
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