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Mathematics 13 Online
OpenStudy (anonymous):

What is the length of ? Round to the nearest hundredth. A.4.24 B.4.83 C.5.75 D.6.09 And how do i solve for these kind of equations?

OpenStudy (anonymous):

OpenStudy (anonymous):

the length of what ?

OpenStudy (anonymous):

I attached the file.

OpenStudy (anonymous):

BC

OpenStudy (anonymous):

\[d^2 = (x2-x1)^2 + (y2-y1)^2\]

OpenStudy (anonymous):

Length BC

OpenStudy (anonymous):

use this formula ..distance between two points

OpenStudy (anonymous):

(x1,y1) (x2,y2)

OpenStudy (anonymous):

Could you explain please, I don't expect for anyone to hand me the answer. But I'm struggling on this.

OpenStudy (anonymous):

ok so tell me what are the coordinates of point B and C ?

OpenStudy (anonymous):

B= 5,1 C= 2, -2

OpenStudy (anonymous):

good .. so given two points in order to find the distance d between them you use the formula i gave you there.. we can take for example point c to have coordinates (x1,y1 ) and point b to have coordinates(x2,y2) do you understand now how to plug your data into the formula ?

OpenStudy (anonymous):

once i fill in x1,y1, and x2,y2 table what do i do??

OpenStudy (anonymous):

x1=5 x2=2 y1=1 y2=2 5-2 + 1 - 2

OpenStudy (anonymous):

d^2 = (5-2)^2 + (1-(-2))^2

OpenStudy (anonymous):

can you find d now?

OpenStudy (anonymous):

nope I'm still having issues,

OpenStudy (anonymous):

5+2=7=/2=3.5 1+2=3=/2=1.5

OpenStudy (anonymous):

d^2 = (5-2)^2 + (1-(-2))^2 d^2 = (3)^2 + (3)^2 d^2 = 9 + 9 d^2 = 18 d = sqrt(18) d = 4.24

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