Solve: -|2m-1| < 2 and please explain how to solve it.
|f(x)|<y -> -y < f(x) < y
|f(x)| > y -> f(x) > y , f(x) < -y
can you do it now ?
um, no, I don't get what you mean by all that..
ok if we divide the equation by -1 what will we get ?
well, my teacher said to change the < to a = when I solve these types of problems so i would get: |2m-1| = -2
ok if you want to do it this way you dont have to divide.. but if you done it already now you know to find m's that satisfy |2m-1| = -2 ?
well, to get rid of the absolute values first, I just seperated it into 2m -1 = -2 and 2m -1 = 2 like my teacher told me to and I got the answers -1/2 and 3/2 but when I tried to check it, it doesn't seem right..
you have to plug now some m<-1/2 like m = -1 -1/2 < m < 3/2 lke m = 1 and m>3/2 like m = 2 in the original equation and see if it holds
when does it hold?
are you there?
yeah sorry, I tried numbers but it didn't work...
can someone else tell me how to solve this or if I'm doing something wrong?
why? when you plug m=-1 what do you get?
i get -4 <2
so it holds isnt it?
-4 is indeed smaller than 2
yes, I know but the answers i got for m and every other number works too which shouldn't be happening
it works for every m
it is obvious.. the original question is negative number < 2 so it always holds i wanted to work on the technique with you
i don't get how that can work though...so the answer is that all numbers work?
yes it is obvious .. all the negative numbers are smaller than 2
if you didnt see it at the original question you could see it when you asked yourself |2m-1| = -2 ? it is never happens .. since left hand side of the equation is always positive !!
ohhhh, okay, thank you :)
yw;)
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