Factoring Question: Factor the following a)8a^2-2ab-21b^2
(2a+3b)(4a-7b)
How did you do that ?
?
on sec ..
ok
If you can't factor this kind of quadratic, omit the second variable (but remember to put it back at the end) and proceed the same way as above 8a^2 - 2a - 21 = 0 a = -3/2, 7/4 (a + 3/2) (a - 7/4) 8 (a + 3/2) (a - 7/4) (2) (4) (a + 3/2) (a - 7/4) (2a + 3) (4a - 7) *(2a + 3b) (4a - 7b)*
How are you getting -3 and 7
I was taught to multiply the a by the c
then find two numbers that add to the "b" and multiply to c and a together
well i was taught like this either way the answer is the same :)
Wait
if we do it my way what two numbers multiply to -168 and add to -2?
i can't figure that part out
-14*12=-168 -14+12=-2
Oh, how did you find that so fast. I can't figure out numbers when they are so inlarged
lol you just have to pratice and study your times tables :)
aha yeah truee, thanks again very much i appreciate the help
You Are Very Welcome :)
Do you mind trying to do another factoring equation that is a bit different?
If you are busy it is okay.
Yah im about to leave some where sorry
Okay thats alright good bye
bye but thanks for the medal
No thank you for the help :)
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