What is the equation of the line that passes through the points (-2, 1) and (1, 10)?

Question

anonymous · Answer

Use (y2 - y1) / (x2 - x1) = m and then put the equation into the point-slope formula of y = mx + b.

anonymous · Answer

(-3,-9) right?

anonymous · Answer

then i put it in point slope formula

anonymous · Answer

Where di you get (-3,-9) ?  You have to use the fraction I gave you in the first post.

anonymous · Answer

so then the equation would be written out 10-1/1-(-2)?

anonymous · Answer

Yes, that will = the slope or m.  Then you can take one of the points and put it into y = mx + b with your numerical value for m.  The only variable left will be b.  Solve for b.  Then, you can go back to y = mx + b with the values of m and b and you will have your equation.

anonymous · Answer

point-slope form is y-y1=M(x-x1)...