Question

Use the quadratic formula to solve the following...
3x^2+2x-8=0

Answer 1

x = [-b +- sqrt(b^2 - 4ac)] / (2a) for equations of the form ax^2 + bx + c = 0. Just substitute. That's all there is to it.

Answer 2

I know the formula but I dont know where my math is going wrong im going to draw what i did

Answer 3

\[x= \frac{ -2\pm \sqrt{2^{2}-4(3)(-8)} }{ 2(3) }\]

then solve it