Question

Graph the function. Label the vertex and axis of symmetry.

y=x^2-5

Answer 1

if \[y = ax^2 + bx + c\]

then the axis of symmetry is

\[x = \frac{-b}{2a}\]

in your equation

a = 1 and b = 0

substitute to find the axis of symmetry

For the vertex, substitute the value of x you found for the axis of symmetry onto the original equation

\[y = x^2 - 5\]

Answer 2

to find the x- intercepts, or roots you need to let y = 0

and solve for x

\[0 = x^2 - 5\]