Mathematics
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OpenStudy (anonymous):
5u+2v=-16, 3u+v=-7 solve by elimination
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OpenStudy (anonymous):
which variable do you want to get rid of first:
5u+2v=-16
3u+v=-7
OpenStudy (anonymous):
u
OpenStudy (anonymous):
why the v seems easier
OpenStudy (anonymous):
ok then
OpenStudy (anonymous):
how
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OpenStudy (anonymous):
so to get rid of the v well multiply that equation by -2
5u+2v=-16
(-2)[3u+v]=-7(-2)
+__________________
OpenStudy (anonymous):
2*3
OpenStudy (anonymous):
ya so your problem will look like this now
5u+2v=-16
-6u-2v=14
+__________________
OpenStudy (anonymous):
ok what is next
OpenStudy (anonymous):
add them up
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OpenStudy (anonymous):
11u,4v
OpenStudy (anonymous):
5u+(-6u)=-u
OpenStudy (anonymous):
-2v+2v=what
OpenStudy (anonymous):
4v
OpenStudy (anonymous):
-2v+2v=0
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OpenStudy (anonymous):
now whats -16+14
OpenStudy (anonymous):
30
OpenStudy (anonymous):
why are you not including the negative in your adding
OpenStudy (anonymous):
sorry 28
OpenStudy (anonymous):
whats 14-16
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
correct so what -16+14
OpenStudy (anonymous):
-4
OpenStudy (anonymous):
how are you getting that
OpenStudy (anonymous):
-6
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OpenStudy (anonymous):
adding -16+14
OpenStudy (anonymous):
you said 14-16=-2
so isnt -16+14 the same thing
OpenStudy (anonymous):
am I subtracting or adding
OpenStudy (anonymous):
what i wrote is the same thing i just switched places, its the same problem
OpenStudy (anonymous):
ok got it is = to 2
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OpenStudy (anonymous):
-2
OpenStudy (anonymous):
now what do we do
OpenStudy (anonymous):
alryte so we have:
-u=-2
we want the u to be positive so well divide both sides by negative 1 since
-u is the same thing as (-1)u
so -u/-1=-2/-1
OpenStudy (anonymous):
ok whats next
OpenStudy (anonymous):
what did u get
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OpenStudy (anonymous):
-u/-1=-2/-1
OpenStudy (anonymous):
ya thats the problem what was the result tho|dw:1348715648139:dw|