Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

for any operator T, show T+T* is self-adjoint and T-T* is skew-adjoint

OpenStudy (anonymous):

I know if T+T* is self adjoint, I need to show T+T*=T*+T. How can I prove T+T*=T*+T

OpenStudy (anonymous):

Just for clarity, you want to show T+T* = (T+T*)* You've basically done the proof for the first one. What does the RHS of your equation imply?

OpenStudy (anonymous):

(T+T*)*=T*+T

OpenStudy (anonymous):

Yes. Although, I would write an extra step just in case the professor doesn't think it's obvious: (T+T*)*=((T*)*+T*)* =T*+T The proof for skew-adjoint is similar. If you want to post it, I can check it if you'd like.

OpenStudy (anonymous):

so if T+T* is self-adjoint T+T* must be equal to (T+T*)*?

OpenStudy (anonymous):

I know if T is a self-adjoint, T=T*

OpenStudy (anonymous):

You're stating the converse, sort of. Also, you have no idea if T is self-adjoint or not. Most of the time, it isn't. All you know is T is an operator and you have T + T*. So, start with that: Let T be an operator and T+T* be given. Then: T+T* = T*+T (since addition is commutative) = ((T*)* + T)* (using definition of transpose: (A+B)* = A*+B*) = (T+T*)* (since (T*)* = T by definition of transpose) And this completes the proof. The proof for skew-adjoint is almost identical.

OpenStudy (anonymous):

T-T*=T*-T =(T*-T)* =((T*)*-T*) =T-T* NO IDEA...

OpenStudy (anonymous):

Write out the equation you're trying to get.

OpenStudy (anonymous):

my question is if T-T* is skew adjoint. T-T* should be equal to what?

OpenStudy (anonymous):

Definition of skew-adjoint: A = -A* Here, your A = T-T* So, what is the equation?

OpenStudy (anonymous):

well... I know that if T is skew adjoint T*=-T, so T=-T* so T-T*=0?

OpenStudy (anonymous):

You're showing T-T* is skew-adjoint, not T. You don't know if T is skew-adjoint. It doesn't have to be. You want T-T* as skew-adjoint. Let A = T-T*. Then, plug it into the definition I gave you. What do you have as your equation?

OpenStudy (anonymous):

T-T*=-T*+T =(-T*+T)* =(-T*)*+T* =-T+T*

OpenStudy (anonymous):

if that's now how you do it. then idk..

OpenStudy (anonymous):

not*

OpenStudy (anonymous):

It's not. You made a slight mistake in your second line. Here's a hint: (Remember: You're trying to show T-T* = -(T-T*)* Notice T-T* = -(-T+T*) Go from there.

OpenStudy (anonymous):

T-T*=-(-T+T*) =-(T*-T)* =-((T*)*-T*) =-(T-T*)

OpenStudy (anonymous):

=-(T*-T)* =-((T*)*-T)* =-(T-T)*

OpenStudy (anonymous):

Close. You made an error distributing the transpose on the 2nd line of your first reply. But, you have the right idea. (Remember: A* + B = (A + B*)* I need to go to bed. I think you should be able to do it from here without a problem though. Have a good night.

OpenStudy (anonymous):

k. Thanks for your help!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!