Mathematics
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OpenStudy (anonymous):
Phillip bought 12 used CDs and DVDs. CDs cost $2 each and DVDs cost $3 each. He spent $31 not including tax. How many DVDs did Phillip buy?
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OpenStudy (cgreenwade2000):
I love explaining these. Are you ready to learn sir/madam?
OpenStudy (anonymous):
Yes
OpenStudy (cgreenwade2000):
Alright. There are 2 unknowns here correct? Tell me what they are.
OpenStudy (anonymous):
how many cds he bought and how many dvds he bought I'm guessing
OpenStudy (cgreenwade2000):
Yes. For now, we'll call the number of CDs by the variable, C. and the number of DVDs will be D.
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OpenStudy (anonymous):
Alright sounds good
OpenStudy (cgreenwade2000):
Using those variables, express the total number of CDs and DVDs he bought.
OpenStudy (anonymous):
12
OpenStudy (cgreenwade2000):
Use the variables in an equation.
OpenStudy (anonymous):
C + D = 31
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OpenStudy (cgreenwade2000):
Incorrect.
What we want is
(the number of CDs) + (the number of DVDs) = 12
OpenStudy (anonymous):
2C + 3D = 12
OpenStudy (cgreenwade2000):
You are getting ahead of yourself.
OpenStudy (cgreenwade2000):
What is the variable for (number of CDs)?
OpenStudy (anonymous):
C?
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OpenStudy (cgreenwade2000):
Yes. We already named it.
So if we know
(the number of CDs) + (the number of DVDs) =12
Write an equation using variables.
OpenStudy (anonymous):
C + D = 12?
OpenStudy (cgreenwade2000):
Correct. That's the first part of the story problem. Now for part 2!
How much does a CD cost?
How much does a DVD cost?
OpenStudy (anonymous):
2$ and 3$
OpenStudy (cgreenwade2000):
So if he bought 3 CDs what would the price be?
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OpenStudy (anonymous):
6$
OpenStudy (cgreenwade2000):
Good. And we get that by (the price of a CD)x(the number of CD)
or 2C
OpenStudy (cgreenwade2000):
So let's write an equation to find the total price of everything altogether. We know it's $31
OpenStudy (anonymous):
Right so 2C + 3D = 31?
OpenStudy (cgreenwade2000):
Yes! Now we have 2 equations
C+D=12
and
2C + 3D =31
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OpenStudy (cgreenwade2000):
Now for the fun stuff.
If C + D =12 ,
then what does D equal?
OpenStudy (anonymous):
3?
OpenStudy (cgreenwade2000):
Don't guess.
OpenStudy (cgreenwade2000):
If C + D = 12
then D = 12 - C
OpenStudy (cgreenwade2000):
TO get that, we would just subtract C on both sides of the equal sign.
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OpenStudy (anonymous):
ok got it
OpenStudy (cgreenwade2000):
Alright so now we know what D equals. We want to substitute it into the second equation.
2C + 3D = 31
2C + 3(12-C) =31
OpenStudy (anonymous):
2C-36+3C=31
2C+3C=31+36
5C=67
OpenStudy (cgreenwade2000):
You have to do that one again. I accidentally wrote it incorrectly.
OpenStudy (cgreenwade2000):
It is +3D
so it should be 3(12-C)
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OpenStudy (anonymous):
so wait the 2D is in front so it should be
2D + 3(12-7) = 31?
OpenStudy (cgreenwade2000):
Where are you getting 7 from?
You should be working on solving this
2C + 3(12-C) =31
OpenStudy (anonymous):
whoops sorry i meant c
OpenStudy (cgreenwade2000):
Go ahead and solve that equation for C
OpenStudy (anonymous):
2C + 3(12-C) =31
2C + 36 - 3C = 31
2C - 3C = 31-36
-1C=-5
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OpenStudy (cgreenwade2000):
Finish solving.
Right now you have -C=-5
Solve so it says C=????
OpenStudy (anonymous):
5
OpenStudy (cgreenwade2000):
:D
So C=5
OpenStudy (cgreenwade2000):
So the number of CDs is what?
OpenStudy (anonymous):
5
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OpenStudy (cgreenwade2000):
Alright. Knowing what C is, can you solve for D?
OpenStudy (anonymous):
C+D=12
5+D=12
D=12-5
D=7
OpenStudy (cgreenwade2000):
So the answer that the problem asks you for is??????
OpenStudy (anonymous):
How many DVDs did Phillip buy. which is 7
OpenStudy (cgreenwade2000):
Congrats!
Feel free to check your answer by plugging in 5 for C and 7 for D in the second equation.
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OpenStudy (anonymous):
Yay thank you very much for your help :)