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Mathematics 13 Online
OpenStudy (anonymous):

f(x)=cos(x) and g(x)=sin(x) what is fOg is it even,odd or neither?

OpenStudy (anonymous):

fOg = cos(sin(x))

OpenStudy (anonymous):

cos is outside.. so it should be even

OpenStudy (amistre64):

should be, but there must be a way to test it out :)

hartnn (hartnn):

yup, if fog(x) = fog(-x) then it is even yup, if fog(x) =- fog(-x) then it is odd else neither so just replace x by -x in fog(x) and find it out

OpenStudy (ghazi):

sin(-x)=- sin x and cos(-x)= cos x....hope this helps you

OpenStudy (ghazi):

fog = cos(sin(x))

OpenStudy (ghazi):

\[\cos(\sin(-x))=\cos(-\sin x)=\cos(\sin x)\]

OpenStudy (ghazi):

does it look like f(-x)=f(x) now match this with the statement given by @hartnn you'll have your answer

hartnn (hartnn):

u almost did all the work for him/her

OpenStudy (ghazi):

because he wasn't doin anything even after lot of hint..sorry for that

OpenStudy (anonymous):

yes i already had that answer F(X) = cos(sin(x)) but it still not clear whether it is odd, even or neither

OpenStudy (ghazi):

if f(-x)=f(x) then it is even

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