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use this formula, if you get same slope then its parallel but if =-1 then its perpendicular
How do I put my equation into that formula?
\[y=\frac{3}{4}(x+3)-2\]find any two points on this line and find the slope. (1,1) and (5,4) lies on this line. so slope = (4-1) /(5-1) = 3/4 so the slope of perpendicular from this line = -4/3|dw:1348754141347:dw|
y-2=(-4/3)(x-9) 3y-6=-4x+36 4x+3y=30
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For parallel line through (9,2) slope of line through (9,2)= 3/4 = slope of the given line \[\frac{x-9}{y-2}=\frac{3}{4}\] \[3y-6=4x-36\] \[4x-3y-36+6=0\] \[4x-3y-30=0\]
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