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x^{3/8} - 12 x^{3/16} + 36 = 0
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Hello there. Any ideas?
can u solve quadratic equations ?
Yeah, but we're supposed to use substitution to solve this one.
right so substitute x^{3/16}=y
Right, I've tried that. And ended up with y^2 - 12y + 36, which I've then reduced to (y-6)^2=0
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But apparently 6 is wrong....
because y=6 x is NOT 6
u need to find x from x^{3/16}=y
Right, right. So I just find what 6^(3/16) equals?
nope
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Then what should I do?
x^{3/16}=y x= y^{16/3} x= 6^{16/3}
got that ^^ ?
Ohhh....okay, yeah. Thank you so much!
welcome ^_^
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Thanks for the medal as well! ^_^
Have a good night.
good night to u, and good morning to me :)
Yes, I suppose so xp
Actually, wait.
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