Question

if AB=2x^2+3x-5,BC=x^2+5x-4,and AC=x^2,solve for x and find AC

Answer 1

is B the mid-point of A and C ?

Answer 2

No

Answer 3

ok, so u have AB=BC
so, 2x^2+3x-5 = x^2+5x -4

Answer 4

subtraxt x^2 from both sides, what u get ?

Answer 5

1x^2+3x-5=5x-4

Answer 6

subtract 5x and add 4 on both sides

Answer 7

1x^2-2X-1=0

Answer 8

now can u solve this quadratic ?

Answer 9

Yes thx'

Answer 10

Sorry No

Answer 11

is the question correct ? verify it

Answer 12

i got x=1+√2 x=1-√2

Answer 13

b^2-4ac is incorrect....

Answer 14

so what are you tring to say did i do it wrong...

Answer 15

x^2-2x-1 = 0
did u use quadratic formula ?

Answer 16

\[x=-b+-\sqrt{b^2-4ac}\]

Answer 17

that formula?

Answer 18

so what is b^2-4ac there ?

Answer 19

oh wait,

Answer 20

x=1+√2 x=1-√2
is correct

Answer 21

how do i plug that in to find out what AC is

Answer 22

(1+√2 )^2 = 1+2+2√2 = 3+2√2

Answer 23

or (1-√2 )^2 = 1+2-2√2 = 3-2√2

Answer 24

ok?

Answer 25

ok