Question

please help me on this math question i only have a couple i need help on :) heres the question

Answer 1

Any ideas on any of them?

Answer 2

yeah i think i have the first one right idk though i need serious help with my math

Answer 3

ok show me what you got on the first one

Answer 4

i said it was 180(n-2)

Answer 5

good

Answer 6

the sum of all the angles in any n-gon is 180(n-2)

Answer 7

okay ,i don't really know any more of them

Answer 8

so a) is 180(n-2)

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b)

now in any regular n-gon, the interior angles are equal, so you take the sum of all the angles and you divide it by n to get the measure of one interior angle

so the measure of each interior angle is

\[\Large \frac{180(n-2)}{n}\]

Answer 9

for any polygon, the sum of the exterior angles is always 360 degrees

how would you find the measure of one exterior angle (all ext angles are equal and there are n of them)?

Answer 10

Idk really would you times n by 360

Answer 11

close, you actually take 360 and you divide it by n

Answer 12

so each ext angle is 360/n degrees

Answer 13

oh okay that makes more since lol

Answer 14

that's great

Answer 15

the only thing left to do is add the answers you got for b) and d)

Answer 16

i didn't do D though

Answer 17

oh, that's 360/n

Answer 18

i thought that was C ok hold on heres what i have A.180(n-2) ,B.180(n-2) divided by n ,C. 360 divided n .

Answer 19

C is just 360

Answer 20

C is the sum of all n ext angles, which is 360 degrees

Answer 21

D is 360/n

Answer 22

oh okay yeah sorry was confused for a minute

Answer 23

that's ok

Answer 24

ok how would i do E again

Answer 25

add the answers from b) and d)

Answer 26

oh okay

Answer 27

tell me what you get