Simplify........... (8x^2)/(x^2-9 ) ∙ (x^2+ 6x+9 )/(16x^3)
try this in the same way as i told you the previous
[8x^2/[(x-3)(x+3)] * [(x+3)^2/(16x^3)] then I Cancel any factor common to a numerator and a denominiator, such as 8,x^2,(x+3), and get [1/(x-3)] * [(x+3)/x] Multiply to get: = (x/3)/[x(x-3)] correct???
just a min let me check
its partly correct you missed writing something
(x+3)/(2x(x-3))
oops what did I miss?
ahhh I see thank you. I really suck at math, I am trying though.
maths is fun.... just love it
I actually hate it, but I am almost 50yrs old and taking this again since high school. I was never taught algebra (the correct way) so I never learned the rules.
I have one more week and my algebra days will be over thank goodness, I wish I did like it.
oh..it ok... you may ask for help any time....
thank you
can you help me with probability
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