a boat travels 10 miles upstream in 2 hours. Going downstream it can travel 30 miles in the same time. Find the speed of the boat in still water. what would the formula look like and how would i solve formula
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OpenStudy (anonymous):
let the speed of boat in still water be x
let speed of stream be y
OpenStudy (anonymous):
when we go up stream the speed gets subtracted:
upstream speed is: x-y
OpenStudy (anonymous):
when we go down stream the speed gets added:
down stream speed is: x+y
OpenStudy (anonymous):
we know speed is distance/time use this
you will get 2 equations
solve them simultaneously
OpenStudy (anonymous):
so what numbers would i put where?
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OpenStudy (anonymous):
30-10/x+y?
OpenStudy (anonymous):
nopes
OpenStudy (anonymous):
10/2=(x-y)
OpenStudy (anonymous):
30/2=(x+y)
OpenStudy (anonymous):
its that
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OpenStudy (anonymous):
i hope you get it now
OpenStudy (anonymous):
but that would give us the answer of 10/4
no 5
OpenStudy (anonymous):
just let me check
OpenStudy (anonymous):
what answer did you get as 10/4
OpenStudy (anonymous):
speed of boat is 10
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OpenStudy (anonymous):
speed of stream will be 5
OpenStudy (anonymous):
some calculation error must be there. check it
hero (hero):
d =rt and r = (b±c)
10 = (b-c)2
30 = (b+c)2
10/2 = b-c
30/2 = b+ c
5 = b-c
15 = b + c
20 = 2b
20/2 = b
10 = b
15 - 10 = c
5 = c
Therefore
b = 10
c = 5
OpenStudy (anonymous):
i did and both times i came out to different equations
the 10/4 was a typing error
i meant to say 20/4 which would give u have