a boat travels 10 miles upstream in 2 hours. Going downstream it can travel 30 miles in the same time. Find the speed of the boat in still water. what would the formula look like and how would i solve formula
let the speed of boat in still water be x let speed of stream be y
when we go up stream the speed gets subtracted: upstream speed is: x-y
when we go down stream the speed gets added: down stream speed is: x+y
we know speed is distance/time use this you will get 2 equations solve them simultaneously
so what numbers would i put where?
30-10/x+y?
nopes
10/2=(x-y)
30/2=(x+y)
its that
i hope you get it now
but that would give us the answer of 10/4 no 5
just let me check
what answer did you get as 10/4
speed of boat is 10
speed of stream will be 5
some calculation error must be there. check it
d =rt and r = (b±c) 10 = (b-c)2 30 = (b+c)2 10/2 = b-c 30/2 = b+ c 5 = b-c 15 = b + c 20 = 2b 20/2 = b 10 = b 15 - 10 = c 5 = c Therefore b = 10 c = 5
i did and both times i came out to different equations the 10/4 was a typing error i meant to say 20/4 which would give u have
ya so thats 5 anf will give you speed of stream
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