Question

how do you factor 27y^3+8?

Answer 1

\(\huge a^3+b^3=(a+b)(a^2-ab+b^2)\)

Answer 2

and here let a=3y and b=2

Answer 3

write 27y^3 as(3y)^3 and ^^

Answer 4

alright but why is a=3 and b=2?

Answer 5

nopes, a=3y, not 3

Answer 6

and u had 8, u can write that as 2^3

Answer 7

so
27y^3+8= (3y)^3+2^3
got this?

Answer 8

yea so u just plug it into the equation and get (3+2)(3^2-(3)(2)+2^2) right?....

Answer 9

NOT 3+2
3y+2
a=3y

Answer 10

alright so then u just solve- so i got (3y+2)(9y^2-6y+4) i this correct?

Answer 11

yes!
that is correct :)

Answer 12

kool thanks!