Mathematics
7 Online
OpenStudy (anonymous):
solve the system of linear equations by graphing. [3x+y=0
[2x+y=2
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OpenStudy (anonymous):
get y by its self do u know how to do that?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
okay well you divide 3x by 0 and what do u get?
OpenStudy (anonymous):
0
OpenStudy (anonymous):
no for equations like this u just keep it in the equation so what you suppose to get is y=3x+0 and now you have something to graph
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OpenStudy (anonymous):
no try and do it on the next one
OpenStudy (anonymous):
i meant now try*
OpenStudy (anonymous):
so is it -3x ?
OpenStudy (anonymous):
no where did u get the negative from?
OpenStudy (anonymous):
i gave u the answer now all u have to do it graph it
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OpenStudy (anonymous):
but u still have to get the 2x+y=2 try to do it
OpenStudy (anonymous):
I don't know how to graph that
OpenStudy (anonymous):
the answer is [y=3x+0
[y=2x+2 you dont know how to graph that?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
do u know what the y-intercept is?
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OpenStudy (anonymous):
and the slope?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
do you know this equation y=mx+b?
OpenStudy (anonymous):
m is the slope and b is the y-intercept?
OpenStudy (anonymous):
I don't understand :(
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OpenStudy (anonymous):
is this your homework?
OpenStudy (anonymous):
yes
OpenStudy (helder_edwin):
u have
\[ \large 3x+y=0\qquad\text{and}\qquad 2x+y=2 \]
OpenStudy (anonymous):
ok
OpenStudy (helder_edwin):
isolating y u have
\[ \large y=-3x\qquad\text{and}\qquad y=-2x+2 \]
ok?
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OpenStudy (anonymous):
ok
OpenStudy (helder_edwin):
the easiest way to graph lines is doing a table. u need only two points.
OpenStudy (anonymous):
ok
OpenStudy (helder_edwin):
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