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Mathematics 17 Online
OpenStudy (anonymous):

Garage = 45% BMWs, 30% Jaguars, and 25% Porches. Of the BMWs, 80% have airbags, 30% Jaguars have airbags, and 40% Porches have airbags. 50% BMWs, 60% Jaguars, and 70% Porches are white. The property of being white is independent from having airbags. You pick a car randomly. If the car has airbags and is white, what is the prob. that it is a BMW?

OpenStudy (anonymous):

@DanielxAK I'm not sure how to do these independent events

OpenStudy (anonymous):

Airbags are dependent on the type of car. Color is dependent on the type of car. Draw two tables, one for each of those. P(AB) =P(A)P(B) if A & B independent. So, find P(A) from your first table and P(B) from your second table. Then, you'll know P(AB).

OpenStudy (anonymous):

What did you define as A and B?

OpenStudy (anonymous):

|dw:1348884874996:dw| and |dw:1348884944449:dw|

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