Find the slope-intercept form for the line satisfying the following conditions. x-intercept is 3, y-intercept is 2/3 The slope-intercept form for the line is?
Can anyone help me finding the slope-intercept?
sure
first tell me what do you understand by x intercept?
i mean what will be the y coordinate
I know we have to do y=mx+b
lets understand few things x intercept implies line crossed x axis, so y coordiante is 0 so the point has the values or coordinates as (3,0) similarly for y intercept x coordiante is 0 so the point has coordinates as (0,2/3)
correct
now find slope m= (2/3-0)/(0-3)
which works out to be -2/9
now use y-y1=m(x-x1) where (x1,y1) can be either (3,0) or (0,2/3)
does that help
how did you get -2/9
(2/3-0)/(0-3)
So basically you have two points (3,0) and (0,2/3) Now insert each point into y = mx + b and solve for m 0 = 3m + b 2/3 = 0m + b -3m = b 2/3 = b -3m = 2/3 m = -2/9 Therefore the equation of the line is y = -2/9(m) + 2/3
Write the function as a set of order pairs. Give the domain and range of it. f(a)=r, f(b)=p, f(c)=t, f(d)=r
Can someone help me?
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