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If a>b and a(b-a)=0, which one or more of the following must be true? i) a=0 ii) b<0 iii) a-b>0
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if a(b-a) = 0 then either a=0 OR b-a =0 did u get this?
@Ventricate did u get how i got that?
anyways , lets continue b-a=0 gives b=a but its given that a>b so b-a=0 is NOT true hence a=0 must be true
ya i get that but the answer key says all three is true
since a>b and a=0 then b must be negative so b<0
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-b>0 (u flip the sign when you multiply by a negative quantity) add a to both sides a-b>a and since a=0 a-b > 0
ahh makes more sense thank you!
welcome ^_^
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