Question

what do u get after differentiating this expression.
shown in attachment.

Answer 1

using the chain rule :

\[f(g(x))' = (df/dg) * (dg/dx)\]

Answer 2

treat g(x) = 0.5x^2+2x-0.78

and f(x) = x^(1/3)

Answer 3

can you do it now ?

Answer 4

i'll try

Answer 5

( 0.5x^2.....-0.78)^1/3
then use chain rule

Answer 6

if you let u = 0.5x^2 + 2x - 0.78 then y = u^(1.3)
what is dy/du ?

Answer 7

i have done it but can anyone check that its right ??

Answer 8

oh wait!
its not (1/3) in the denominator
its 3 in the denominator

Answer 9

oh yeah.. thanks
is the rest correct ??

Answer 10

yes.. :)

Answer 11

cheers :)))

Answer 12

(x+2)/3 . (0.5 ^2 + 2x - 0.78) ^-2/3