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Physics 13 Online
OpenStudy (anonymous):

an object at rest begins to rotate with a constant acceleration. if the object rotates trough an angle in the time, t, through what angle did it rotate in the time t/2?

OpenStudy (anonymous):

same idea as uniformly accelerated motion in straight line Theta(t) = acc*0.5*t^2

OpenStudy (anonymous):

so one quarter of

OpenStudy (anonymous):

Forget the fact that it's rotating for a while- same thing. If something is accelerating and every second an LED blinks, the blinks will look something like this|dw:1348938007009:dw| ,with acceleration rightwards. So in this case the average speed in the first half a second is more than the average speed in the second half a second, so the distance travel led in first half< distance in second half. That's the intuition, but mathematically, Mikael is correct.

OpenStudy (anonymous):

Or: distance is equal to the area under a velocity-time graph.|dw:1348938213833:dw|

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