Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

A) in which quadrant does the point (-52, -35) lie. B) Determine if the following points are solutions of the equation. (2,-3) , (-2,3) for 2x-y=7

OpenStudy (anonymous):

Do you know where each quadrant is?

OpenStudy (anonymous):

well it says consider each ordered pair.

OpenStudy (anonymous):

yea it asks for the qaudrant?

OpenStudy (anonymous):

|dw:1348977194057:dw|

OpenStudy (anonymous):

huh mine does not have a graph. i get u though.

OpenStudy (anonymous):

my key pad is missing up. guys im sorry about that.

OpenStudy (anonymous):

Question a was about quadrants, those are the 4 different ones

OpenStudy (anonymous):

yea i know i have to determine where i think -52,-35 belong at.

OpenStudy (anonymous):

Well if you go left and then down, which one would you be in?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

Thats correct

OpenStudy (anonymous):

wat about the second part?

OpenStudy (anonymous):

For that one you plug in the x coordinate for x and the y coordinate for y, and then if the equation equals 0 the point is a solution

OpenStudy (anonymous):

yea because basically i mean ur just trying to solve how u get the answer. of the x and y. if u solve for x than y equals 0 and samething happens when u do for y right.

OpenStudy (anonymous):

I misread that, plug those in and if it equal 7 then the point is a solution

OpenStudy (anonymous):

so 2(2)-(-3)=7

OpenStudy (anonymous):

no nevermind i think they cant be plug in right.

OpenStudy (anonymous):

What do you mean?

OpenStudy (anonymous):

I just plugged the first point into the equation

OpenStudy (anonymous):

oh yea ok i was wrong ur right.

OpenStudy (anonymous):

i get it now.

OpenStudy (anonymous):

so is the first point a solution?

OpenStudy (anonymous):

i think so.

OpenStudy (anonymous):

the second is not i think im doing the work right now on my paper.

OpenStudy (anonymous):

You're right. the second one isnt

OpenStudy (anonymous):

yea i thought so i was about to doubt myself a bit.

OpenStudy (anonymous):

thx

OpenStudy (anonymous):

You're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!