Question

find m so that the roots of the equation

Answer 1

\[ \frac{ x^{2}-bx }{ax-c}=\frac{ m-1 }{ m+1}\]

Answer 2

may be equal in magnitude and opposite in sign

Answer 3

in Ax^2+Bx+C=0, could you derive that B=0 for such equations?

Answer 4

yes and then

Answer 5

cross-multiply the equation, you have and equate the co-efficient of x =0

Answer 6

because you won't have x term in such equations

Answer 7

how ??

Answer 8

how to cross-multiply or how we won't have x-term ??

Answer 9

cross-multiply this \[\frac{ x ^{2}-bx }{ax-c }=\frac{ m-1 }{ m+1 }\]

Answer 10

@hartnn

Answer 11

did u get this ?