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derivative of f(x)=(1/3) at x=(2/3)
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Since function is equal to constant, derivative function is equal to zero, so for all x, especially at 2/3, the answer is zero.
Does this make sense?
kind of
We know that f(x) = 1/3 If we derivantive f(x), then f'(x) = 0 Derivative of constant is always equal to zero. (Yes, 1/3 is constant) There is no x variable to plug in so no matter what x is, f'(x) is always zero. Does this clear everything?
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