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Mathematics 20 Online
OpenStudy (gabylovesyou):

Please solve each of the inequalities below and graph the solution on a number line. It will be beneficial to you to show work on all problems so your instructor may provide specific feedback. However, to receive full credit for this assignment, you must show work for #4 and 5. You may either use a paint program, power point, or any program you choose to create the number line graphs, draw the graphs by hand and scan, or describe the graph in words. For example, x > 3 would be “x is greater than 3. The graph would have an open circle on 3 with shading to the right.”

OpenStudy (gabylovesyou):

#1-5 (1 point each) 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1 4. 2(x + 5) > 8x – 8 5. –2(x – 3) ≥ 5 – (x + 3)

OpenStudy (gabylovesyou):

@jim_thompson5910 PLEASE HELP ME!! I BEGG :)

jimthompson5910 (jim_thompson5910):

Let's do these one at a time

jimthompson5910 (jim_thompson5910):

1. x – 3 > –9

jimthompson5910 (jim_thompson5910):

How do we solve that?

OpenStudy (gabylovesyou):

MMMMMMMM We have to figure out what X is

OpenStudy (gabylovesyou):

How do you do that? lol

jimthompson5910 (jim_thompson5910):

you want to isolate x

jimthompson5910 (jim_thompson5910):

or get x all by itself

jimthompson5910 (jim_thompson5910):

how do we move that -3 over?

OpenStudy (gabylovesyou):

mmmm by doing it to both sides??

jimthompson5910 (jim_thompson5910):

What can we add/subtract to both sides to get rid of that -3?

OpenStudy (gabylovesyou):

x? :/

jimthompson5910 (jim_thompson5910):

-3 + what = 0

OpenStudy (gabylovesyou):

3

jimthompson5910 (jim_thompson5910):

good, so add 3 to both sides, what do you get?

OpenStudy (gabylovesyou):

x > -6

jimthompson5910 (jim_thompson5910):

perfect

jimthompson5910 (jim_thompson5910):

so how do we graph this? any ideas?

OpenStudy (gabylovesyou):

Can you tell me step by step without words how we did that so i put it on my paper

jimthompson5910 (jim_thompson5910):

x - 3 > -9 x - 3+3 > -9+3 x > -6

jimthompson5910 (jim_thompson5910):

That sums up what we did

OpenStudy (gabylovesyou):

alright :)

jimthompson5910 (jim_thompson5910):

how do we graph x > -6 ?

OpenStudy (gabylovesyou):

mmmmmmm idk

jimthompson5910 (jim_thompson5910):

To graph the inequality x > -6, draw out a number line. Then plot an open circle at -6. Then shade to the right of the open circle.

OpenStudy (gabylovesyou):

Im going to put that ^^^ it says that i can do it in words so :)

jimthompson5910 (jim_thompson5910):

yeah i prefer that over trying to draw (i suck at drawing lol)

OpenStudy (gabylovesyou):

LMAO me too :)

OpenStudy (gabylovesyou):

now.... number 2

jimthompson5910 (jim_thompson5910):

–2x + 1 ≤ –11

jimthompson5910 (jim_thompson5910):

What's the first step?

OpenStudy (gabylovesyou):

mmmmm its a guess.....i know its wrong but i think you have to subtract 1 from each side

jimthompson5910 (jim_thompson5910):

it's a good guess because it's correct

OpenStudy (gabylovesyou):

ohh lol yaaay

jimthompson5910 (jim_thompson5910):

–2x + 1 ≤ –11 –2x + 1-1 ≤ –11-1 –2x ≤ –12

jimthompson5910 (jim_thompson5910):

what's next?

OpenStudy (gabylovesyou):

divide both sides by -2 ?

jimthompson5910 (jim_thompson5910):

good, this will flip the sign

jimthompson5910 (jim_thompson5910):

–2x + 1 ≤ –11 –2x + 1-1 ≤ –11-1 –2x ≤ –12 x ≥ –12/(-2) x ≥ 6

OpenStudy (gabylovesyou):

alright :)

jimthompson5910 (jim_thompson5910):

next graphing this

OpenStudy (gabylovesyou):

ok...

jimthompson5910 (jim_thompson5910):

how do we do that?

OpenStudy (gabylovesyou):

draw a number line

jimthompson5910 (jim_thompson5910):

good, what's next?

OpenStudy (gabylovesyou):

plot a closed circle at 6

jimthompson5910 (jim_thompson5910):

good, then what?

OpenStudy (gabylovesyou):

shade to the...........right?

jimthompson5910 (jim_thompson5910):

perfect

OpenStudy (gabylovesyou):

ok hold on let me write that

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (gabylovesyou):

ok number 3

jimthompson5910 (jim_thompson5910):

10 < –3x + 1

jimthompson5910 (jim_thompson5910):

first step?

OpenStudy (gabylovesyou):

mmmmmm subtract 1 from both sides?!

jimthompson5910 (jim_thompson5910):

good, giving you what?

OpenStudy (gabylovesyou):

9 < -3x

jimthompson5910 (jim_thompson5910):

then what's next?

OpenStudy (gabylovesyou):

divide both sides by -3

jimthompson5910 (jim_thompson5910):

good, keep in mind the sign will flip

jimthompson5910 (jim_thompson5910):

so doing that gives you what?

OpenStudy (gabylovesyou):

3 < x

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

9 < –3x 9/(-3) > –3x/(-3) -3 > x and that flips to this x < -3

jimthompson5910 (jim_thompson5910):

so the full steps are

jimthompson5910 (jim_thompson5910):

10 < –3x + 1 10 -1 < –3x + 1 -1 9 < –3x 9/(-3) > –3x/(-3) -3 > x x < -3

OpenStudy (gabylovesyou):

To graph the inequality, draw out a number line. Then plot an open circle on -3 Then shade to the right of the open circle.

jimthompson5910 (jim_thompson5910):

close, it's to the left

jimthompson5910 (jim_thompson5910):

everything else is perfect though

OpenStudy (gabylovesyou):

ohh ok :)

jimthompson5910 (jim_thompson5910):

< means shade to the left > means shade to the right

OpenStudy (gabylovesyou):

alright.... number 4

jimthompson5910 (jim_thompson5910):

2(x + 5) > 8x – 8

jimthompson5910 (jim_thompson5910):

First step is to distribute

jimthompson5910 (jim_thompson5910):

2(x + 5) > 8x – 8 2x + 10 > 8x – 8

jimthompson5910 (jim_thompson5910):

what's next?

OpenStudy (gabylovesyou):

subtract 10 from both sides?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

what does that give you?

OpenStudy (gabylovesyou):

2x > 8x - 18

jimthompson5910 (jim_thompson5910):

then what?

OpenStudy (gabylovesyou):

divide both sides by 2??

jimthompson5910 (jim_thompson5910):

not yet, you subtract 8x from both sides

OpenStudy (gabylovesyou):

Add 18 to both sides?

jimthompson5910 (jim_thompson5910):

no, subtract 8x from both sides

jimthompson5910 (jim_thompson5910):

you want to get all the x terms to the left side

OpenStudy (gabylovesyou):

-6x - 18 ??

OpenStudy (gabylovesyou):

oh wait

OpenStudy (gabylovesyou):

idk

jimthompson5910 (jim_thompson5910):

you forgot the inequality sign

jimthompson5910 (jim_thompson5910):

-6x > -18

jimthompson5910 (jim_thompson5910):

then what?

OpenStudy (gabylovesyou):

divide both sides by -6

jimthompson5910 (jim_thompson5910):

giving you ???

OpenStudy (gabylovesyou):

x > 3

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

the sign will flip because you're dividing both sides by a negative number

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