Question

an isosceles triangle has two sides of length 9x+3. the perimeter of the triangle is 30x+10. Determine the ratio of the base to the perimeter in simplified form. State the restriction on x

Answer 1

First find the base. Remember the base is just the perimeter minus the other two legs.

Answer 2

Base would be 13x-6

Answer 3

now what ?

Answer 4

s two sides of length 9x+3

Answer 5

so you don't have the correct base yet

Answer 6

so what would I do :S

Answer 7

\[30x+10 - 2(9x+3)\]

Answer 8

you have 2 legs of 9x+3 and 3 legs that add up to the permiter

Answer 9

okayy so i added those two and subtracted from the perimeter and got 13x-6

Answer 10

or 12x-6 *

Answer 11

check your arithmetic (or algebra)

Answer 12

wait, 12x-4

Answer 13

better
now make the ratio of base over perimeter
factor out the constants

Answer 14

altho I think it is 12x+4 , don't you think?

Answer 15

yes you are right !

Answer 16

now make the ratio of base over perimeter
factor out the constants

Answer 17

thank you so much :)

Answer 18

what do you get?

Answer 19

2/5 :)

Answer 20

State the restriction on x

Answer 21

even though you cancelled (3x+1), you could not do that if that expression is 0. 0/0 is undefined.

Answer 22

oh yeah

Answer 23

so x≠ -1/3

Answer 24

There is also the triangle inequality.

Answer 25

As well as the fact that a triangle can't have negatively sized legs.

Answer 26

It's an ambiguous question. It could be talking about the ratio, but I don't think it is.

Answer 27

I would say \[12x+4\gt 0\]As well as\[9x+3>0\]Then I would solve for \(x\). @sheetalvee