Question

Ok, the problem asks to graph the line passing through the given point and having the given slope. Give the slope-intercept form of the equation of the line if possible.

I don't understand this at all, no matter how much I work on it.

(1,-1), m=-2/3

Answer 1

us the info to right the equation that you will use to draw the line
y=mx+c
so m= -2/3
then y=(-2/3)x+c
then you want the c value so put the coordinate in to the equation
(1, -1)
y= -1 x=1
-1=(-2/3)x1+c
-1+(2/3)=c
-1/3=c
so thut the values together and you get
y=(-2/3)x-(1/3)

Answer 2

Still does not make sense at all.

Answer 3

now that you have this equation you can plot the graph

Answer 4

It says it is wrong every time I plot it.

Answer 5

what is saying that it is wrong?

Answer 6

I have no clue what I am doing wrong on the plotting. I put one point at -2/3 and the other one at 1/3.

Answer 7

no thats not what you should do. first you create a domain for your x value. this is a list of x values you want to use. then put each x value in the equation and solve for y.