Question

In figure below if a charge of 4uc flows from the 6V battery to plate P of the 1 uF capacitor. what charge flow from
a - Q to R

b - S to the battery

c - What is the pd across C1 and C2

d - What is capacitance of C2

e - What is the single capacitor which is equivalent to C1 and C2 in series and what charge would it store?

Answer 1

a. 4uC
b. 4uC
c. 6V
d.
\[Q = C _{eq}V\]
\[\frac{ 1 }{ C _{eq}} = \frac{ 1 }{ C _{1}}+\frac{ 1 }{ C _{2}}\]
\[Q = ( \frac{ 1 }{ C _{1}}+\frac{ 1 }{ C _{2}})^{-1}V\]

Answer 2

make sense?

Answer 3

use conservation of charge

Answer 4

@Algebraic! please can you explain how u derived a,b,c

Answer 5

if +4uC is on the plate at P then -4uC will be on the plate at Q meaning +4uC flowed to the plate at R meaning that there's - 4 uC at the plate at S meaning +4uC flowed to the terminal of the battery.
For c. ) I did the total voltage drop, which must be 6V, you could also do the drop per capacitor, and then find the capacitance of c2 from that. I didn't do it that way, I combined the solution to d and e into one part instead.