Question

Help asap please

Answer 1

\[\frac{ \frac{ 12(x-8) }{ x^2-4x-32 } }{ \frac{ 6(x^2-x-2) }{ 3(x+1) } }\] is your first step

Answer 2

You can guess that you'll be canceling x+1 and x-8, so you might want to try factoring those out of the quadratics

Answer 3

ok