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Mathematics 14 Online
OpenStudy (anonymous):

Factor 6x^9-30x^7

OpenStudy (tamtoan):

what is the common factor of 6 and 30, and what is the common factor of x^9 and x^7 ?

OpenStudy (anonymous):

Ok that is what i thought i should be doing. It is 3x^7

OpenStudy (tamtoan):

30/6 = 5 right? so your number factor is 6....x^7 is another factor , that's correct, but after that you can still factor again..can you write them out?

OpenStudy (anonymous):

my answer would be 6x^7(1+5x^2)?

OpenStudy (tamtoan):

shouldn't it be - instead of + ?

OpenStudy (tamtoan):

also the x^2 is with the coefficient 6...not 30 :)

OpenStudy (anonymous):

yes it should lol negative!

OpenStudy (anonymous):

so it would be 6x^7(5x^2-1)

OpenStudy (tamtoan):

no :) if you try to multiply in again...you will get 30x^9 ...is your first term, and that wouldn't be true with your original expression. right? :)

OpenStudy (anonymous):

right. so where am I messing up at?

OpenStudy (anonymous):

6x^7(5-x^2)

OpenStudy (tamtoan):

when you factor, try to do each term carefully. ..first take out the 6 see what's inside, then take out the x^7 ...then see what's left write like this, straight down so you can see it easily 6x^9 - 30x^7 = 6x^7( x^2 - 5) = 6x^7{[x - sqrt(5)(x + sqrt(5)]} the last step is from formula : a^2 - b^2 = (a - b)(a + b) you got that right?

OpenStudy (anonymous):

I typed you my awnser was that correct?

OpenStudy (tamtoan):

your answer was not correct, because you switch the term around inside the parenthesis

OpenStudy (tamtoan):

when you factor, each step, if you go backward and multiply in, you should get the previous step correctly

OpenStudy (anonymous):

so I should have 6x^7(x^2-5)

OpenStudy (tamtoan):

yeah, that or go further one more step as i typed earlier.

OpenStudy (anonymous):

i dont get your next step.

OpenStudy (anonymous):

6x^7(x^2-5)(x^2+5) ?

OpenStudy (tamtoan):

no no, when you get to ...6x^7(x^2 - 5)... to use formular a^2 - b^ = (a - b)(a + b) ......look at x^2 - 5 your x = a (so x^2 = a^2) your b = sqrt(5) (squareroot of 5) ...so that your b^2 = 5 you get this ? i must go in couple mins. i want to help you through this so let me know soon

OpenStudy (tamtoan):

as i did earlier for you : this is it...you can check again : (i'll copy and paste the earlier work) 6x^9 - 30x^7 = 6x^7( x^2 - 5) = 6x^7{[x - sqrt(5)(x + sqrt(5)]}

OpenStudy (tamtoan):

hope you enjoy :) and have a good evening. i must go now

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