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Mathematics 15 Online
OpenStudy (anonymous):

PLEASE HELP :)! i have a whole worksheet on factoring and i dont know how to do it! here are some of them! please explain and help me work them out.

OpenStudy (anonymous):

\[a ^{2}-5a+6\]

hartnn (hartnn):

what are the 2 numbers whose product is 6 and sum = -5 ?

OpenStudy (anonymous):

\[a ^{2}-8a-9\]

OpenStudy (anonymous):

hmm 2 numbers whose product is 6 are 3 and 3?

hartnn (hartnn):

but sum is not -5 wait! 3*3 is not 6 :P

OpenStudy (anonymous):

haha thought you meant plus :p okay so -3 and 2 ?

hartnn (hartnn):

-3*2 is -6 not +6

hartnn (hartnn):

hint: both are negative

OpenStudy (anonymous):

ergggg i dont know im sorry

hartnn (hartnn):

try -2 and -3 ?? is product 6 ? is sum -5 ?

OpenStudy (anonymous):

Your product, 6 is positive, and the sum, -5, is negative, so the two numbers which are factors of 6 wil both be negative. Your factors have to both be negative, otherwise you could not get a -5 sum from two positive numbers.

OpenStudy (anonymous):

@tcarroll010 oh okay so could you show me how to properly write that?

OpenStudy (anonymous):

Well, @hartnn did give you the right numbers. The factoring form is (a +- some number)(a +- the other number)

OpenStudy (anonymous):

okay so, (a-2)(a-3) ?

hartnn (hartnn):

yup

OpenStudy (anonymous):

Yes! But to verify that and to consolidate your understanding, you should try going in the other direction and multiplying it out. Do this in the beginning with these types of problems. If you go backward and forward, you will gain a lot of understanding and insight.

OpenStudy (anonymous):

thankyou so much guys! so just one more example to make sure i got it lol. if i had n^2-2n-24 it would be (n+4)(n-6) @hartnn @tcarroll010

hartnn (hartnn):

yup, correct!

OpenStudy (anonymous):

thankyou!

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

does it matter if i were to write it vice versa? like (n-6)(n+4)

hartnn (hartnn):

DOES NOT MATTER.

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