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If P is a second degree polynomial of such that P(2)=4,P'(2)=1,P''(2)=6, find the value of P(1)
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Lets ax^2+bx+c be the polynomial now as per the given conditions put P(2), P'(2) and P''(2) and now find the values of a , b,c from these three equations. You will get the polynomial
I did that but then when I put in P(1) I cant find the answer choice.
put the value 1 in the polynomial you got.
Ok I don't know if I did it right but when i did P'(2)=4a+b=1, b=-11 then P''(2)=2a=6 so a=3 then P(2)=4a^2+2b+c=4, c+-10..... then i got P(x)=3x^2-11x-10 but then when i plugged in 1 i get -18 but its not an answer choice
then options of answers may be wrong
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I guess so ... well thankyou for trying to help me
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