Question

Use the quadratic formula to find the zeros of y=2x^2+8x+1

Answer 1

\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}\]

Answer 2

thats not one of the options @ParthKohli

Answer 3

@Coolsector

Answer 4

@yahoo!

Answer 5

you should use what parthkohli wrote ..
ax^2+bx+c =0
use what he wrote

Answer 6

it's not an option though @Coolsector

Answer 7

no .. look
ax^2+bx+c =0
in your case
a=2
b =8
c=1

now plug it into what parthkoli wrote and you will get the zeros ..

Answer 8

Look at this.

Answer 9

@Coolsector

Answer 10

if you plug it into what partkholi wrote you get :
\[\frac{ -8 \pm \sqrt{64-8} }{ 4 }\]