how do you point 2y-3x=1 on a slope graph

Question

anonymous · Answer

let x=0 find value of y------>got the point (0,y)
let y=0 find the value of x----->''                 "(x,0)

anonymous · Answer

first find y in function of x :

$$y =  \frac{ 1+3x }{ 2 }$$


so you got a line  in the form $$y = ax +b$$

$$a$$ is the slope (3/2) and $$  b$$  is the linear coefficient (1/2)


with x = 0  you got y = 1/2 thats where the line crossed the y axis and with y = 0 you have $$\frac{ 1 }{ 2 } + \frac{ 3x }{ 2 } = 0$$x = -1/3( where the line crosses the x axis and you can plot it now.

anonymous · Answer

thanks so much... i have been working on this promble for a hour