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Biology 8 Online
OpenStudy (anonymous):

What does it mean if I am given 40U of enzyme?

OpenStudy (raspberryjam):

U as in mu the greek letter? Does it look like this? μ?

OpenStudy (anonymous):

U as in units of enzyme activity

OpenStudy (raspberryjam):

Ohhh gotcha. It's the amt of enzymes that will convert 1 micromol of substance per min.

OpenStudy (raspberryjam):

Er I meant substrate not substance

OpenStudy (anonymous):

yeah. got that part. i'm trying to find the final enzyme concentration. the problem just said 40 units of Hae enzyme.

OpenStudy (raspberryjam):

It didn't tell you the amount of substrate that got converted?

OpenStudy (raspberryjam):

Or give you a time lol?

OpenStudy (anonymous):

Maybe i'm interpreting the question incorrectly but this is what i have: Set up a dna digest of the sample that contains 10 ug of dna sample & 40 units of Hae III enzyme. the ff is given: stock dna = 3.5ug/ul ; enzyme stock is 12units/ul.

OpenStudy (raspberryjam):

So wouldn't that just be \[\frac{40u}{12u}=3.33\mu L \] of the enzyme? Then \[\frac{10\mu g}{3.5\mu g}=2.86\mu L \]

OpenStudy (raspberryjam):

is it asking you to make a specific volume of it?

OpenStudy (anonymous):

thanks! i actually figured it out last night while we were talking about it! it was a duh! moment for me. yes, i would need 3.33uL of the enzyme. wish me luck on my midterm!

OpenStudy (raspberryjam):

Haha you won't need it :)

OpenStudy (anonymous):

so how do you calculate your final volume when you have 3.33ul of enzyme, 3.5ug/ul of stock and 3.33 uls of 10X buffer?

OpenStudy (anonymous):

I forgot to say I have 2.85uls of DNA.

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