could someone help me with this i also need the steps on how you figured it out, 6=x+2/3
you want to solve for x?
yes and x+2/3 is a fraction
\[6 = \frac{x+2}3\] or \[6 = x + \frac 23\]
first one
x+2 over 3
hmm so \[6 = \frac{x+2}3\] are you familiar with "cross multiplication"?
yes
good. so perform cross multiplication ehre
here*
im not sure on how to do it though
i go to a virtual school and some problems almost need to be seen done in order to understand them
hmm okay then for example you have \[2 = \frac x3\] cross multiplying 3 to 2 \[\implies 2\times 3 = x\] then simplify\[\implies 6 = x\] got it?
ok so the answer is x=6?
in my example
notice how my example is not the same as your question
ok thank you for your help
welcome
6= x+2/3 6(3)= x+2/3(3) - you get rid of the denominator which is 3 18=x+2 18-2= x+2-2 16= x
thank you Natasha would you have time to help me with one more?
np and yeah sure
-5=s-3
you want to isolate the "s" so you do -5+3= s-3+3 to remove the 3 and then s= -2
see now when i see it done already for me i get it!! then i also have this last one 5/13t =-9
when you go to a virtual school you dont always get to see it done by someone
ok so you would get rid of the 13 first by multiplying it on both sides: 5/13(13)t= -9(13) so you would get 5t= -117, you would then divide by 5 on both sides: 5/5t= -117/5 so t= 23.4
thank you very much!! I really appreciate your help
aha anytime! (:
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