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Mathematics 11 Online
OpenStudy (anonymous):

In the diagram, figure PMNO is the image of figure ABCD.

OpenStudy (anonymous):

OpenStudy (anonymous):

do you want the name of the image B?

OpenStudy (anonymous):

all it is is just a trapezoid and its just shifted over, so everything is congruent

OpenStudy (anonymous):

is that what you were looking for?

OpenStudy (anonymous):

you must add me as a fan to message me

OpenStudy (anonymous):

@JakeV8 please help me on this question

OpenStudy (anonymous):

um, you don't have to add as a fan to message. But you can add as a fan just because you want to... :)

OpenStudy (anonymous):

lol could u please help with this question??

OpenStudy (anonymous):

Yeah @ilikephysics2 is correct. Think of ABCD as some wire frame you are holding up... the shadow of it, or image of it, is PMNO. So find the point on PMNO that corresponds to the point B on ABCD

OpenStudy (anonymous):

The question actually asks for the angle, not the point, so your answer would be <___

OpenStudy (anonymous):

I don't get it I will show you... you mean like <M is similar to <B

OpenStudy (anonymous):

angle P angle M Angle N Angle A

OpenStudy (anonymous):

you actually do get it... :) yes... if you held your wire frame ABCD by the corner where angle B is, you would see the shadow of your hand holding angle M on the shadow image.

OpenStudy (anonymous):

ahhhh ok

OpenStudy (anonymous):

wohoo!

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Do you have the answers :) ?

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