a=b(1/c-1/d) isolate c the problem says to divide both sides by b first
thats right, since we need to isolate c,
and we see that, b is multiplied there, so we perform the opposite operation - divide b,
\(a = b(\frac{1}{c} - \frac{1}{d})\) divide b both sides, \(\frac{a}{b} = \frac{1}{c} - \frac{1}{d}\)
then I need to add 1/d to both sides
perfect !
I just dont know what to do when I am left with 1/c
\(\frac{a}{b} + \frac{1}{d} = \frac{1}{c}\)
\(\frac{1}{\frac{a}{b} + \frac{1}{d}} \ = c\)
if you wanto simplify, u may simplify left hand side, by taking LCD...
but we are done wid what we asked, we isolated the c !!!!!!
but i think i need to simplify the left side.
good :) simplify it by multiplying numerator & denominator wid the LCD = bd
LCD, like the drugs? I dont know what it is.
\(\frac{bd*1}{bd*(\frac{a}{b} + \frac{1}{d})} \ = c \) \(\frac{bd}{ad+b} \ = c \)
lol, LCD = Least Common Denominator
oh. that makes more sense. I was concerned that I was going to have to do drugs to pass my math classes
first thing pops up in mind for LCD is, Liquid Crystal Display hw come u get into drugs and all hmm
Im clean! I promise!
lol you're funny ;p
good luck wid ur math exams :)
It was on some online homework and I just got the answer back and it said I didnt have to simplify the fractions. so 1/(a/b+1/d) would have worked. If only I knew to begin with :/
Thanks for your help
lol its okay yw !
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